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# 6.4. Multiple Input and Output Channels¶

While we have described the multiple channels that comprise each image (e.g., color images have the standard RGB channels to indicate the amount of red, green and blue), until now, we simplified all of our numerical examples by working with just a single input and a single output channel. This has allowed us to think of our inputs, convolutional kernels, and outputs each as two-dimensional arrays.

When we add channels into the mix, our inputs and hidden representations both become three-dimensional arrays. For example, each RGB input image has shape \(3\times h\times w\). We refer to this axis, with a size of 3, as the channel dimension. In this section, we will take a deeper look at convolution kernels with multiple input and multiple output channels.

## 6.4.1. Multiple Input Channels¶

When the input data contains multiple channels, we need to construct a convolution kernel with the same number of input channels as the input data, so that it can perform cross-correlation with the input data. Assuming that the number of channels for the input data is \(c_i\), the number of input channels of the convolution kernel also needs to be \(c_i\). If our convolution kernel’s window shape is \(k_h\times k_w\), then when \(c_i=1\), we can think of our convolution kernel as just a two-dimensional array of shape \(k_h\times k_w\).

However, when \(c_i>1\), we need a kernel that contains an array of
shape \(k_h\times k_w\) *for each input channel*. Concatenating
these \(c_i\) arrays together yields a convolution kernel of shape
\(c_i\times k_h\times k_w\). Since the input and convolution kernel
each have \(c_i\) channels, we can perform a cross-correlation
operation on the two-dimensional array of the input and the
two-dimensional kernel array of the convolution kernel for each channel,
adding the \(c_i\) results together (summing over the channels) to
yield a two-dimensional array. This is the result of a two-dimensional
cross-correlation between multi-channel input data and a *multi-input
channel* convolution kernel.

In Fig. 6.4.1, we demonstrate an example of a two-dimensional cross-correlation with two input channels. The shaded portions are the first output element as well as the input and kernel array elements used in its computation: \((1\times1+2\times2+4\times3+5\times4)+(0\times0+1\times1+3\times2+4\times3)=56\).

To make sure we really understand what is going on here, we can
implement cross-correlation operations with multiple input channels
ourselves. Notice that all we are doing is performing one
cross-correlation operation per channel and then adding up the results
using the `sum()`

function.

Let’s import the libraries before jumping into the concept of multiple input and output channels.

```
%mavenRepo snapshots https://oss.sonatype.org/content/repositories/snapshots/
%maven ai.djl:api:0.7.0-SNAPSHOT
%maven org.slf4j:slf4j-api:1.7.26
%maven org.slf4j:slf4j-simple:1.7.26
%maven net.java.dev.jna:jna:5.3.0
%maven ai.djl.mxnet:mxnet-engine:0.7.0-SNAPSHOT
%maven ai.djl.mxnet:mxnet-native-auto:1.7.0-b
```

```
import ai.djl.*;
import ai.djl.ndarray.NDArray;
import ai.djl.ndarray.NDList;
import ai.djl.ndarray.NDManager;
import ai.djl.ndarray.index.NDIndex;
import ai.djl.ndarray.types.DataType;
import ai.djl.ndarray.types.Shape;
import ai.djl.ndarray.NDArrays;
```

```
NDManager manager = NDManager.newBaseManager();
public NDArray corr2D(NDArray X, NDArray K) {
long h = K.getShape().get(0);
long w = K.getShape().get(1);
NDArray Y = manager.zeros(new Shape(X.getShape().get(0) - h + 1, X.getShape().get(1) - w + 1));
for (int i = 0; i < Y.getShape().get(0); i++) {
for (int j = 0; j < Y.getShape().get(1); j++) {
NDArray temp = X.get(i + ":" + (i + h) + "," + j + ":" + (j + w)).mul(K);
Y.set(new NDIndex(i + "," + j), temp.sum());
}
}
return Y;
}
public NDArray corr2dMultiIn(NDArray X, NDArray K) {
long h = K.getShape().get(0);
long w = K.getShape().get(1);
// First, traverse along the 0th dimension (channel dimension) of `X` and
// `K`. Then, add them together
NDArray res = manager.zeros(new Shape(X.getShape().get(0) - h + 1, X.getShape().get(1) - w + 1));
for (int i = 0; i < X.getShape().get(0); i++) {
for (int j = 0; j < K.getShape().get(0); j++) {
if (i == j)
res = res.add(corr2D(X.get(new NDIndex(i)), K.get(new NDIndex(j))));
}
}
return res;
}
```

```
[IJava-executor-0] INFO ai.djl.mxnet.jna.LibUtils - Downloading libgfortran.so.3 ...
[IJava-executor-0] INFO ai.djl.mxnet.jna.LibUtils - Downloading libgomp.so.1 ...
[IJava-executor-0] INFO ai.djl.mxnet.jna.LibUtils - Downloading libquadmath.so.0 ...
[IJava-executor-0] INFO ai.djl.mxnet.jna.LibUtils - Downloading libmxnet.so ...
```

We can construct the input array `X`

and the kernel array `K`

corresponding to the values in the above diagram to validate the output
of the cross-correlation operation.

```
NDArray X = manager.create(new Shape(2, 3, 3), DataType.INT32);
X.set(new NDIndex(0), manager.arange(9));
X.set(new NDIndex(1), manager.arange(1, 10));
X = X.toType(DataType.FLOAT32, true);
NDArray K = manager.create(new Shape(2, 2, 2), DataType.INT32);
K.set(new NDIndex(0), manager.arange(4));
K.set(new NDIndex(1), manager.arange(1, 5));
K = K.toType(DataType.FLOAT32, true);
corr2dMultiIn(X, K);
```

```
ND: (2, 2) gpu(0) float32
[[ 56., 72.],
[104., 120.],
]
```

## 6.4.2. Multiple Output Channels¶

Regardless of the number of input channels, so far we always ended up
with one output channel. However, as we discussed earlier, it turns out
to be essential to have multiple channels at each layer. In the most
popular neural network architectures, we actually increase the channel
dimension as we go higher up in the neural network, typically
downsampling to trade off spatial resolution for greater *channel
depth*. Intuitively, you could think of each channel as responding to
some different set of features. Reality is a bit more complicated than
the most naive interpretations of this intuition since representations
are not learned independent but are rather optimized to be jointly
useful. So it may not be that a single channel learns an edge detector
but rather that some direction in channel space corresponds to detecting
edges.

Denote by \(c_i\) and \(c_o\) the number of input and output channels, respectively, and let \(k_h\) and \(k_w\) be the height and width of the kernel. To get an output with multiple channels, we can create a kernel array of shape \(c_i\times k_h\times k_w\) for each output channel. We concatenate them on the output channel dimension, so that the shape of the convolution kernel is \(c_o\times c_i\times k_h\times k_w\). In cross-correlation operations, the result on each output channel is calculated from the convolution kernel corresponding to that output channel and takes input from all channels in the input array.

We implement a cross-correlation function to calculate the output of multiple channels as shown below.

```
public NDArray corrMultiInOut(NDArray X, NDArray K) {
long cin = K.getShape().get(0);
long h = K.getShape().get(2);
long w = K.getShape().get(3);
// Traverse along the 0th dimension of `K`, and each time, perform
// cross-correlation operations with input `X`. All of the results are
// merged together using the stack function
NDArray res = manager.create(new Shape(cin, X.getShape().get(1) - h + 1, X.getShape().get(2) - w + 1));
for (int j = 0; j < K.getShape().get(0); j++) {
res.set(new NDIndex(j), corr2dMultiIn(X, K.get(new NDIndex(j))));
}
return res;
}
```

We construct a convolution kernel with 3 output channels by
concatenating the kernel array `K`

with `K+1`

(plus one for each
element in `K`

) and `K+2`

.

```
K = NDArrays.stack(new NDList(K, K.add(1), K.add(2)));
K.getShape()
```

```
(3, 2, 2, 2)
```

Below, we perform cross-correlation operations on the input array `X`

with the kernel array `K`

. Now the output contains 3 channels. The
result of the first channel is consistent with the result of the
previous input array `X`

and the multi-input channel, single-output
channel kernel.

```
corrMultiInOut(X, K);
```

```
ND: (3, 2, 2) gpu(0) float32
[[[ 56., 72.],
[104., 120.],
],
[[ 76., 100.],
[148., 172.],
],
[[ 96., 128.],
[192., 224.],
],
]
```

## 6.4.3. \(1\times 1\) Convolutional Layer¶

At first, a \(1 \times 1\) convolution, i.e., \(k_h = k_w = 1\), does not seem to make much sense. After all, a convolution correlates adjacent pixels. A \(1 \times 1\) convolution obviously does not. Nonetheless, they are popular operations that are sometimes included in the designs of complex deep networks. Let us see in some detail what it actually does.

Because the minimum window is used, the \(1\times 1\) convolution loses the ability of larger convolutional layers to recognize patterns consisting of interactions among adjacent elements in the height and width dimensions. The only computation of the \(1\times 1\) convolution occurs on the channel dimension.

Fig. 6.4.2 shows the cross-correlation computation using
the \(1\times 1\) convolution kernel with 3 input channels and 2
output channels. Note that the inputs and outputs have the same height
and width. Each element in the output is derived from a linear
combination of elements *at the same position* in the input image. You
could think of the \(1\times 1\) convolutional layer as constituting
a fully-connected layer applied at every single pixel location to
transform the \(c_i\) corresponding input values into \(c_o\)
output values. Because this is still a convolutional layer, the weights
are tied across pixel location. Thus the \(1\times 1\) convolutional
layer requires \(c_o\times c_i\) weights (plus the bias terms).

Let us check whether this works in practice: we implement the \(1 \times 1\) convolution using a fully-connected layer. The only thing is that we need to make some adjustments to the data shape before and after the matrix multiplication.

```
public NDArray corr2dMultiInOut1x1(NDArray X, NDArray K) {
long channelIn = X.getShape().get(0);
long height = X.getShape().get(1);
long width = X.getShape().get(2);
long channelOut = K.getShape().get(0);
X = X.reshape(channelIn, height * width);
K = K.reshape(channelOut, channelIn);
NDArray Y = K.dot(X); // Matrix multiplication in the fully connected layer
return Y.reshape(channelOut, height, width);
}
```

When performing \(1\times 1\) convolution, the above function is
equivalent to the previously implemented cross-correlation function
`corrMultiInOut()`

. Let us check this with some reference data.

```
X = manager.randomUniform(0f, 1.0f, new Shape(3, 3, 3));
K = manager.randomUniform(0f, 1.0f, new Shape(2, 3, 1, 1));
NDArray Y1 = corr2dMultiInOut1x1(X, K);
NDArray Y2 = corrMultiInOut(X, K);
System.out.println(Math.abs(Y1.sum().getFloat() - Y2.sum().getFloat()) < 1e-6);
```

```
true
```

## 6.4.4. Summary¶

Multiple channels can be used to extend the model parameters of the convolutional layer.

The \(1\times 1\) convolutional layer is equivalent to the fully-connected layer, when applied on a per pixel basis.

The \(1\times 1\) convolutional layer is typically used to adjust the number of channels between network layers and to control model complexity.

## 6.4.5. Exercises¶

Assume that we have two convolutional kernels of size \(k_1\) and \(k_2\) respectively (with no nonlinearity in between).

Prove that the result of the operation can be expressed by a single convolution.

What is the dimensionality of the equivalent single convolution?

Is the converse true?

Assume an input shape of \(c_i\times h\times w\) and a convolution kernel with the shape \(c_o\times c_i\times k_h\times k_w\), padding of \((p_h, p_w)\), and stride of \((s_h, s_w)\).

What is the computational cost (multiplications and additions) for the forward computation?

What is the memory footprint?

What is the memory footprint for the backward computation?

What is the computational cost for the backward computation?

By what factor does the number of calculations increase if we double the number of input channels \(c_i\) and the number of output channels \(c_o\)? What happens if we double the padding?

If the height and width of the convolution kernel is \(k_h=k_w=1\), what is the complexity of the forward computation?

Are the variables

`Y1`

and`Y2`

in the last example of this section exactly the same? Why?How would you implement convolutions using matrix multiplication when the convolution window is not \(1\times 1\)?